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Risk Warning: Trading CFDs and FX is risky. It isn't suitable for everyone and if you are a professional client, you could lose substantially more than your initial investment. You don't own or have rights in the underlying assets. Past performance is no indication of future performance and tax laws are subject to 下载Olymp Trade移动应用程序 change. The information on this website is general in nature and doesn't take 下载Olymp Trade移动应用程序 into account your personal objectives, financial circumstances, or needs. You should consider whether you’re part of our target market by reviewing our TMD, and read our PDS and 下载Olymp Trade移动应用程序 下载Olymp Trade移动应用程序 other legal documents to ensure you fully understand the risks before you make any trading decisions. We encourage you to seek independent advice if necessary.

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Codeforces Round #765 (Div. 2) B. Elementary Particles

Evil_boy__ 于 2022-01-13 15:05:33 发布 327 收藏 1

Martians are actively engaged in interplanetary trade. Olymp City, the Martian city known for its spaceport, has become a place where goods from all the corners of our Galaxy come. To deliver even more freight from faraway planets, 下载Olymp Trade移动应用程序 Martians need fast spaceships.

A group of scientists conducts experiments to build a fast engine for the new spaceship. In the current experiment, there are nn elementary particles, the ii-th of them has type aiai.

Denote a subsegment of the particle sequence (a1,a2,…,ana1,a2,…,an) as a sequence (al,al+1,…,aral,al+1,…,ar) for some left bound ll and right bound rr (1≤l≤r≤n1≤l≤r≤n). For instance, the sequence (1 4 2 8 5 7)(1 4 2 8 5 7) for l=2l=2 and r=4r=4 has the sequence (4 2 8)(4 2 8) as a subsegment. Two subsegments are considered different if at least one bound of 下载Olymp Trade移动应用程序 those subsegments differs.

Note that the subsegments can be equal as sequences but still considered different. For example, consider the sequence (1 1 1 1 1)(1 1 1 1 1) and two of its subsegments: one with l=1l=1 and r=3r=3 and another with l=2l=2 and r=4r=4. Both subsegments are equal to (1 1 1)(1 下载Olymp Trade移动应用程序 下载Olymp Trade移动应用程序 1 1), but still considered different, as their left and right bounds differ.

The scientists want to conduct a reaction to get two different subsegments of the same length. Denote this length kk. The resulting pair of subsegments must be harmonious, i. e. for some ii (1≤i≤k1≤i≤k) it must be true that the types of particles 下载Olymp Trade移动应用程序 on the ii-th position are the same for these two subsegments. For example, the pair (1 7 3)(1 7 3) and (4 7 8)(4 7 8) is harmonious, as both subsegments have 77 on the second position. The pair (1 2 3)(1 2 3) and (3 1 2)(3 1 2) is not 下载Olymp Trade移动应用程序 harmonious.

The longer are harmonious subsegments, the more chances for the scientists to design a fast engine. So, they asked you to calculate the maximal possible length of harmonious pair made of different subsegments.

The first line contains an integer tt (1≤t≤1001≤t≤100) 下载Olymp Trade移动应用程序 下载Olymp Trade移动应用程序 — the number of test cases. The following are descriptions of the test cases.

The 下载Olymp Trade移动应用程序 下载Olymp Trade移动应用程序 first line contains an integer nn (2≤n≤1500002≤n≤150000) — the amount of elementary particles in 下载Olymp Trade移动应用程序 the sequence.

The second line contains nn integers aiai (1≤ai≤1500001≤ai≤150000) — types of elementary 下载Olymp Trade移动应用程序 particles.

It is guaranteed that the sum of nn over all test cases does not exceed 3⋅1053⋅105.

For each test, print a single integer, maximal possible length of 下载Olymp Trade移动应用程序 harmonious pair made of different subsegments. If such pair does not exist, print −1−1 下载Olymp Trade移动应用程序 下载Olymp Trade移动应用程序 instead.

The first test case is shown on the picture below:

As you can 下载Olymp Trade移动应用程序 see from it, you may choose the subsegments (2 1 3 4)(2 1 3 4) and (3 1 5 2)(3 1 5 2), which are a harmonious pair. Their length is equal to 44, so the answer is 44.

In the second test case, you need to take two subsegments: one with l=1l=1 and r=5r=5, and one with l=2l=2 and r=6r=6. It's not hard to observe that these segments are a harmonious pair and considered different even though they are both equal to (1 1 1 1 1)(1 1 1 1 1).

In the 下载Olymp Trade移动应用程序 third test case, you cannot make a harmonious pair, so the answer is −1−1.下载Olymp Trade移动应用程序

思路:用结构体存下这个数组的值和下边,然后快排(数值从小到大,下标从小到大),遍历一遍数组,如果当前和前一位值相同就max(答案,i + n - l);

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